What is the molarity of a solution containing 72.9 grams of HCL in Enough for the to make 500ML of solution.
To determine the molarity of the HCl solution, we need to use the formula:
Molarity = moles of solute / volume of solution (in liters)
Step 1: Convert the given mass of HCl to moles:
molarity = (72.9 g HCl) / (36.46 g/mol HCl)
molarity = 1.999 moles HCl
Step 2: Convert the given volume of solution to liters:
volume = 500 mL = 0.5 L
Step 3: Calculate the molarity:
molarity = 1.999 moles / 0.5 L
molarity = 3.998 M or approximately 4.0 M
Therefore, the molarity of the HCl solution is 4.0 M.
To calculate the molarity (M) of a solution, you need two pieces of information: the moles of solute and the volume of the solution in liters.
Step 1: Convert the given mass of HCl into moles.
The molar mass of HCl is 36.46 g/mol. Divide the given mass of HCl by its molar mass to get moles.
moles of HCl = 72.9 g / 36.46 g/mol = 2 moles
Step 2: Convert the given volume of the solution from milliliters (mL) to liters (L).
Divide the given volume by 1000 to convert it into liters.
volume of solution = 500 mL / 1000 mL/L = 0.5 L
Step 3: Calculate the molarity.
Divide the moles of solute (HCl) by the volume of the solution in liters.
molarity (M) = moles of HCl / volume of solution
= 2 moles / 0.5 L
= 4 M
Therefore, the molarity of the solution is 4 M.