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11 minutes ago
The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
score. Number of students
80. 5
85 9
90 5
95 6
100 9
To find the mean, we need to first calculate the sum of all the scores and the number of students:
Sum of scores = (80 x 5) + (85 x 9) + (90 x 5) + (95 x 6) + (100 x 9) = 400 + 765 + 450 + 570 + 900 = 3085
Number of students = 5 + 9 + 5 + 6 + 9 = 34
Mean = Sum of scores / Number of students = 3085 / 34 = 90.735
Rounding to the nearest 10th, the mean is 90.7.
Find the 8th term of the arithmetic sequence 5x + 7, x +12, -3x + 17
To find the mean (average) of the scores, follow these steps:
1. Multiply each score by the number of students who received that score:
- 80 * 5 = 400
- 85 * 9 = 765
- 90 * 5 = 450
- 95 * 6 = 570
- 100 * 9 = 900
2. Add up the products from step 1:
400 + 765 + 450 + 570 + 900 = 3085
3. Add up the total number of students:
5 + 9 + 5 + 6 + 9 = 34
4. Divide the sum from step 2 by the total number of students from step 3:
3085 / 34 = 90.73529411764706
5. Round the mean to the nearest 10th:
The mean of the scores to the nearest 10th is approximately 90.7.
To find the mean of the scores to the nearest 10th, you need to calculate the average of the scores.
1. Multiply each score by the corresponding number of students:
80 * 5 = 400
85 * 9 = 765
90 * 5 = 450
95 * 6 = 570
100 * 9 = 900
2. Add up these products:
400 + 765 + 450 + 570 + 900 = 3085
3. Add up the number of students:
5 + 9 + 5 + 6 + 9 = 34
4. Divide the sum of products by the sum of the number of students:
3085 / 34 ≈ 90.735
5. Round the mean to the nearest 10th:
90.735 rounded to the nearest 10th is approximately 90.7.
So, the mean of the scores to the nearest 10th is 90.7.