What is the mass percent of sucrose in a solution Obtained by mixing 225 gram of An aqueous solution, that is 6.25% sucrose by mass with 135 gram. Of an aqueous solution that is 8.20% sucrose by Mass.
To solve the problem, we need to first calculate the total mass and total amount of sucrose in the mixture.
Total mass = 225 g + 135 g = 360 g
Amount of sucrose in the first solution = 6.25% x 225 g = 14.06 g
Amount of sucrose in the second solution = 8.20% x 135 g = 11.07 g
Total amount of sucrose in the mixture = 14.06 g + 11.07 g = 25.13 g
The mass percent of sucrose in the mixture is:
mass percent = (amount of sucrose ÷ total mass) x 100%
mass percent = (25.13 g ÷ 360 g) x 100% ≈ 6.98%
Therefore, the mass percent of sucrose in the mixture is approximately 6.98%.
To find the mass percent of sucrose in the resulting solution, we need to calculate the total mass of sucrose and the total mass of the solution.
First, let's calculate the total mass of sucrose:
Mass of sucrose in the first solution = 6.25% of 225 grams
= (6.25 / 100) x 225
= 14.06 grams
Mass of sucrose in the second solution = 8.20% of 135 grams
= (8.20 / 100) x 135
= 11.07 grams
Total mass of sucrose = Mass of sucrose in the first solution + Mass of sucrose in the second solution
= 14.06 grams + 11.07 grams
= 25.13 grams
Next, let's calculate the total mass of the resulting solution:
Total mass of the solution = Mass of the first solution + Mass of the second solution
= 225 grams + 135 grams
= 360 grams
Finally, the mass percent of sucrose in the resulting solution can be calculated:
Mass percent of sucrose = (Total mass of sucrose / Total mass of the solution) x 100
= (25.13 grams / 360 grams) x 100
≈ 6.98%
Therefore, the mass percent of sucrose in the resulting solution is approximately 6.98%.