Calculate the mass of 2.94*10^ 17 atoms of hafnium.
The atomic mass of hafnium is 178.49 g/mol, which means that one mole of hafnium contains 6.022 x 10^23 atoms.
To calculate the mass of 2.94 x 10^17 atoms of hafnium, we can use the following formula:
mass = (number of atoms/molecular or atomic mass) x molar mass
mass = (2.94 x 10^17/6.022 x 10^23) x 178.49 g/mol
mass = 2.94 x 10^17/6.022 x 10^23 x 178.49 g
mass = 3.48 x 10^-6 g
Therefore, the mass of 2.94 x 10^17 atoms of hafnium is approximately 3.48 x 10^-6 g.
To calculate the mass of 2.94*10^17 atoms of hafnium, we need to know the atomic mass of hafnium. The atomic mass of hafnium (Hf) is approximately 178.49 g/mol.
Step 1: Convert the given number of atoms to moles.
Number of atoms = 2.94 * 10^17 atoms
Avogadro's number (NA) = 6.022 * 10^23 atoms/mol
Number of moles = Number of atoms / Avogadro's number
Number of moles = 2.94 * 10^17 atoms / 6.022 * 10^23 atoms/mol
Step 2: Calculate the mass using the molar mass of hafnium.
Molar mass of hafnium (Hf) = 178.49 g/mol
Mass = Number of moles * Molar mass
Mass = (2.94 * 10^17 atoms / 6.022 * 10^23 atoms/mol) * 178.49 g/mol
Now, let's calculate the mass:
Mass ≈ (2.94 * 10^17 / 6.022 * 10^23) * 178.49
Mass ≈ 2.94 * 178.49 / 6.022
Mass ≈ 0.0871 grams
Therefore, the mass of 2.94*10^17 atoms of hafnium is approximately 0.0871 grams.