calculate the mass of 8.22*10^23 atoms of rubidium
To calculate the mass of 8.22*10^23 atoms of rubidium, we need to use the atomic mass of rubidium (Rb), which is 85.47 g/mol.
We can use this equation to calculate the mass:
mass = (number of atoms) x (atomic mass)
mass of rubidium = 8.22*10^23 x 85.47 g/mol
mass of rubidium = 7.03 x 10^25 g
Therefore, the mass of 8.22*10^23 atoms of rubidium is 7.03 x 10^25 g.
calculate no. of atoms
To calculate the number of atoms, we need to know the mass of the sample and the atomic mass of the element.
If we know the mass of the sample in grams, we can use the following formula:
number of atoms = (mass of sample / atomic mass) x Avogadro's constant
where Avogadro's constant is 6.022 x 10^23 atoms/mol.
For example, if we have 1 gram of carbon, which has an atomic mass of 12.01 g/mol, we can calculate the number of atoms as follows:
number of atoms = (1 g / 12.01 g/mol) x 6.022 x 10^23 atoms/mol
number of atoms = 4.998 x 10^22 atoms
Therefore, there are 4.998 x 10^22 atoms in 1 gram of carbon.
and for 8.22*10^23 mol of rubidium
It is incorrect to say "8.22*10^23 mol of rubidium". Mol is a unit of amount of substance, not a quantity of atoms. However, if you meant "8.22*10^23 atoms of rubidium", then we can calculate the amount of substance (in moles) as follows:
amount of substance (in moles) = (number of atoms) / Avogadro's constant
amount of substance (in moles) = (8.22 x 10^23) / 6.022 x 10^23 atoms/mol
amount of substance (in moles) = 1.37 moles
Therefore, there are 1.37 moles of rubidium in 8.22*10^23 atoms of rubidium.
Calculate the mass of 9. 96 * 10^ 26 atoms of tellerium
To calculate the mass of 9.96 x 10^26 atoms of tellurium, we need to use the atomic mass of tellurium (Te), which is 127.60 g/mol.
We can use this equation to calculate the mass:
mass = (number of atoms) x (atomic mass)
mass of tellurium = 9.96 x 10^26 x 127.60 g/mol
mass of tellurium = 1.27 x 10^29 g
Therefore, the mass of 9.96 × 10^26 atoms of tellurium is 1.27 × 10^29 g.