A glass cup of juice is found to have a pOH of 11.4 .calculate the concentration of the hydrogen ions in the juice
pOH + pH = 14
pH = 14 - 11.4 = 2.6
pH = -log[H+]
2.6 = -log[H+]
[H+] = 10^-2.6
[H+] = 2.51 x 10^-3 M
Therefore, the concentration of the hydrogen ions in the juice is 2.51 x 10^-3 M.
To calculate the concentration of hydrogen ions (H+) in a solution, we first need to find the concentration of hydroxide ions (OH-).
Given that the pOH of the juice is 11.4, we can use the equation:
pOH = -log[OH-]
Let's rearrange the equation to solve for [OH-]:
[OH-] = 10^(-pOH)
Substituting the value of pOH = 11.4 into the equation, we have:
[OH-] = 10^(-11.4)
Calculating this value, we find that [OH-] ≈ 3.98 x 10^(-12) M.
Next, we can use the fact that in water at 25°C, the concentration of H+ and OH- are equal (1 x 10^(-7) M) to find the concentration of H+:
[H+] = [OH-]
[H+] = 3.98 x 10^(-12) M
Therefore, the concentration of hydrogen ions (H+) in the juice is approximately 3.98 x 10^(-12) M.