8.00 grams of calcium chloride CaCl^2 to is dissolved in 1.000KG of water. Assume that the ionic compound CaCl^2 t separates completely into Ca^2+ and Cl^-. when it dissolves in water. How many moles of each ion are present in the solution.
First, we need to calculate the number of moles of CaCl^2 in the solution:
Molar mass of CaCl^2 = 40.08 g/mol (for Ca) + 2(35.45 g/mol) = 110.98 g/mol
Number of moles of CaCl^2 = 8.00 g / 110.98 g/mol = 0.072 moles
Since CaCl^2 dissociates completely into Ca^2+ and Cl^- ions, we have the same number of moles of each ion as the original compound. Therefore, there are 0.072 moles of Ca^2+ and 0.144 moles of Cl^- in the solution.
explain me in more detail
Sure, I'd be happy to explain in more detail!
We know that 8.00 grams of calcium chloride (CaCl2) is dissolved in 1.000 kg (or 1000 g) of water. Our goal is to find out how many moles of each ion are present in the resulting solution.
To do this, we first need to calculate the number of moles of calcium chloride in the solution. To do this, we use the molar mass of calcium chloride. The molar mass is the sum of the atomic masses of all the elements in the compound. For calcium chloride, the molar mass is:
molar mass of CaCl2 = (molar mass of Ca) + (2 x molar mass of Cl)
molar mass of CaCl2 = 40.08 g/mol + (2 x 35.45 g/mol)
molar mass of CaCl2 = 110.98 g/mol
This means that one mole of calcium chloride (CaCl2) weighs 110.98 grams.
Now, we can calculate the number of moles of calcium chloride in the solution using the following formula:
moles of a substance = mass of substance / molar mass of substance
In this case, we can plug in the values we know:
moles of CaCl2 = 8.00 g / 110.98 g/mol
moles of CaCl2 = 0.072 mol
So we have 0.072 moles of calcium chloride in the solution.
Since calcium chloride (CaCl2) dissociates completely into Ca2+ and Cl- ions when it dissolves in water, we can assume that the number of moles of each ion in the solution is the same as the number of moles of the original compound.
Therefore, we have:
- 0.072 moles of Ca2+
- 2 x 0.072 moles = 0.144 moles of Cl-
Overall, there are 0.072 moles of Ca2+ and 0.144 moles of Cl- in the solution.
so we are assuming 0.0072 moles are of calcium when it dissolves and same for chloride
Yes, that's correct. When calcium chloride (CaCl2) dissolves in water, it dissociates completely into its constituent calcium (Ca2+) and chloride (Cl-) ions. This means that every molecule of CaCl2 that dissolves in water produces one calcium ion and two chloride ions in the solution. Since we know the number of moles of calcium chloride in the solution (0.072 moles), we can assume that we have the same number of moles of calcium ions and twice that number of moles of chloride ions in the solution. So, we can say that we have 0.072 moles of Ca2+ and 2 x 0.072 = 0.144 moles of Cl- in the solution.
thanks :-)
You're welcome! Feel free to ask if you have any more questions.
do u know jokes
Sure, I know jokes. Here's one:
Why did the tomato turn red?
Because it saw the salad dressing!