Evaluate limit of 3√(x²+7) as x approaches 3
To evaluate the limit of 3√(x²+7) as x approaches 3, we substitute 3 for x and simplify:
3√(3²+7) = 3√16 = 3 x 2 = 6
Therefore, the limit of 3√(x²+7) as x approaches 3 is 6.
To evaluate the limit of √(x²+7) as x approaches 3, we can substitute the value of x into the expression and simplify.
Let's substitute x = 3 into the expression:
√(3²+7) = √(9+7) = √16 = 4
Therefore, the limit of √(x²+7) as x approaches 3 is 4.