For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 21 N acts on a certain object, the acceleration of the object is 7 /ms2. If the acceleration of the object becomes
5 /ms2 , what is the force?
Using the formula for direct variation, we know that:
force = constant x acceleration
To find the constant, we can plug in the initial values:
21 = constant x 7
Solving for the constant, we get:
constant = 3
Now that we know the constant, we can use it to find the force when the acceleration changes:
force = constant x acceleration
force = 3 x 5
force = 15 N
Therefore, the force acting on the object when its acceleration is 5 /ms2 is 15 N.
We are given the first scenario where the force acting on the object is 21 N and the acceleration is 7 m/s^2. We are also given the second scenario where the acceleration becomes 5 m/s^2, and we need to find the force.
Let's assume that the force (F) and acceleration (a) have a direct relationship, which means they are directly proportional to each other.
Using the formula for direct proportionality, we can write:
F1 / a1 = F2 / a2
where F1 and a1 are the initial force and acceleration, and F2 and a2 are the final force and acceleration.
Plugging in the given values, we have:
21 N / 7 m/s^2 = F2 / 5 m/s^2
Now, we can solve for F2:
(21 N) * (5 m/s^2) = (7 m/s^2) * F2
105 N·m/s^2 = 7 m/s^2 * F2
Simplifying further, we get:
105 N = 7 F2
Dividing both sides of the equation by 7, we find:
F2 = 105 N / 7
F2 = 15 N
Therefore, when the acceleration of the object becomes 5 m/s^2, the force acting on the object is 15 N.