If the nth term of a sequence is given by (-2)^1-n,what is the fourth term of the sequence
To find the fourth term of the sequence, we need to substitute n = 4 into the formula for the nth term:
(-2)^(1-4) = (-2)^(-3) = -1/8
Therefore, the fourth term of the sequence is -1/8.
To find the fourth term of the sequence given by the nth term (-2)^(1-n), we substitute n = 4 into the equation.
Let's calculate:
(-2)^(1-4) = (-2)^(-3) = 1/((-2)^3) = 1/(-8) = -1/8
Therefore, the fourth term of the sequence is -1/8.
To find the fourth term of the sequence, we need to substitute n = 4 into the given formula.
The formula for the nth term of the sequence is (-2)^(1-n).
Let's substitute n = 4 into the formula:
(-2)^(1-4) = (-2)^(-3)
To simplify this expression, we can rewrite (-2)^(-3) as 1/(-2)^3.
Now, let's calculate (-2)^3:
(-2)^3 = -2 * -2 * -2 = -8
Therefore, the fourth term of the sequence is:
1/(-8) = -1/8
Hence, the fourth term of the sequence is -1/8.