When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass
8 kg
, the acceleration of the object is
7 /ms2
. If the same force acts upon another object whose mass is
28 kg
, what is this object's acceleration?
Using the formula for inverse variation:
a1 * m1 = a2 * m2
where a1 and m1 are the acceleration and mass of the first object, and a2 and m2 are the acceleration and mass of the second object (with the same force acting upon it).
Plugging in the values given:
7 * 8 = a2 * 28
Solving for a2:
a2 = (7 * 8) / 28 = 2 m/s^2
Therefore, the acceleration of the second object is 2 m/s^2.
To find the acceleration of the second object, we can use the equation for inverse variation:
acceleration = k / mass
where k is the constant of variation.
We can plug in the values given in the problem to find the value of k:
7 m/s^2 = k / 8 kg
To find the value of k, we can cross-multiply and solve for k:
k = 7 m/s^2 * 8 kg
k = 56 N
Now that we have the value of k, we can use it to find the acceleration of the second object:
acceleration = k / mass
acceleration = 56 N / 28 kg
acceleration = 2 m/s^2
Therefore, the second object's acceleration is 2 m/s^2.