Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is
5 L
, the pressure is
158 kPa
(kilopascals). What is the pressure when the volume is
2 L
?
Using Boyle's Law:
P1V1 = P2V2
Where P1 is the initial pressure (158 kPa), V1 is the initial volume (5 L), P2 is the final pressure (unknown), and V2 is the final volume (2 L).
Plugging in the numbers:
158 kPa * 5 L = P2 * 2 L
790 kPa = P2
Therefore, the pressure when the volume is 2 L is 790 kPa.
To find the pressure when the volume is 2 L, we can use Boyle's Law. Boyle's Law states that the volume of a gas varies inversely with the pressure.
We know that when the volume is 5 L, the pressure is 158 kPa. Let's call this pressure P1 and the volume V1.
P1 = 158 kPa
V1 = 5 L
We need to find the pressure when the volume is 2 L. Let's call this pressure P2 and the volume V2.
V2 = 2 L
According to Boyle's Law, the product of the initial pressure and initial volume is equal to the product of the final pressure and final volume.
P1 * V1 = P2 * V2
Substituting the known values:
158 kPa * 5 L = P2 * 2 L
Simplifying the equation:
790 kPa * L = P2 * 2 L
Dividing both sides of the equation by 2 L:
P2 = 790 kPa / 2
P2 = 395 kPa
Therefore, the pressure when the volume is 2 L is 395 kPa.