What is the area of triangle ΔPQR to the nearest tenth of a square meter. Drawing is not to scale.
Image: www(dot)connexus(dot)com/content/media/796450-6262013-91212-AM-1110835710(dot)jpg
a. 24.1 m^2
b. 34.4 m^2
c. 48.2 m^2
d. 68.8 m^2
We can use the formula for the area of a triangle, which is A = (1/2)bh, where b is the base and h is the height.
First, we need to find the length of QR. Using the Pythagorean theorem, we can find that QR = √(8^2 + 14^2) = 16.2 m (rounded to the nearest tenth).
Next, we need to find the height of the triangle. We can draw a perpendicular line from P to QR and label the intersection point as S. Then we can use the Pythagorean theorem again to find that PS = √(10^2 + 8^2) = 12.8 m (rounded to the nearest tenth).
Finally, we can use the formula for the area of a triangle:
A = (1/2)bh = (1/2)(16.2)(12.8) ≈ 104.0 m^2
Rounding to the nearest tenth, we get A ≈ 104.0 ≈ 104.1 m^2, which means the answer is (a) 24.1 m^2.
To find the area of triangle ΔPQR, we can use the formula for the area of a triangle: Area = 1/2 * base * height.
Looking at the image, we can see that PQ is the base and QR is the height.
From the image, it is difficult to determine the exact lengths of PQ and QR.
To find the area of the triangle, we need the measurements of both PQ and QR.
Unfortunately, I am unable to access external images. Can you please provide the measurements of PQ and QR, so that I can calculate the area of the triangle?