haggs had 2 paddocks of cows. he knew that the cows in paddock A at 20% more food than cows in paddock B. he wanted to distribute 110kg of food so the cows in both paddocks would finish the food at same time. How much food should be put In each paddock
Let's call the amount of food in paddock B "x".
According to the problem, the cows in paddock A eat 20% more food than those in paddock B. This means they eat 1.2x (120% of x) amount of food.
Together, the cows in both paddocks eat x + 1.2x = 2.2x amount of food.
We know that 110kg of food needs to be distributed, so we can set up an equation:
x + 1.2x = 110
Simplifying:
2.2x = 110
x = 50
So paddock B needs 50kg of food.
To find out how much food paddock A needs, we can use the fact that it eats 20% more than paddock B:
1.2x = 1.2(50) = 60
So paddock A needs 60kg of food.
Therefore, 50kg of food should be put in paddock B and 60kg of food should be put in paddock A.
To solve this problem, let's assume the amount of food needed for the cows in paddock B as 'x' kg.
According to the problem, the cows in paddock A need 20% more food than the cows in paddock B. So, the cows in paddock A will require 20% additional food, which is 0.20x kg.
The total amount of food needed for the cows in paddock A is the sum of food needed for paddock B and the additional 20%: x kg + (0.20x kg) = 1.20x kg.
Since the total amount of food available is 110 kg, the equation becomes: x kg + 1.20x kg = 110 kg.
Combining like terms, we get: 2.20x kg = 110 kg.
To solve for x, divide both sides of the equation by 2.20:
x = 110 kg / 2.20 = 50 kg.
Therefore, the cows in paddock B require 50 kg of food.
To find the amount of food needed for paddock A, we can substitute the value of x back into the equation: 1.20x kg = 1.20 * 50 kg = 60 kg.
Hence, 50 kg of food should be put in paddock B, and 60 kg of food should be put in paddock A.