A fair dice is tossed twice. Find probability of the event 'you get '2 dots' both times you toss ?
The probability of getting 2 dots on one toss of a fair die is 1/6. As each toss is independent, the probability of getting 2 dots on two tosses is (1/6) x (1/6) = 1/36. Therefore, the probability of getting '2 dots' both times you toss a fair die is 1/36.
To find the probability of getting "2 dots" both times you toss a fair dice, we need to consider the total number of possible outcomes and the favorable outcomes.
Total number of possible outcomes when a fair dice is tossed twice = 6 × 6 = 36 (since each toss has 6 possible outcomes)
Favorable outcomes: There is only one outcome where we get "2 dots" both times, which is (2, 2).
Therefore, the probability of getting "2 dots" both times you toss is 1/36.