let g(x)=5x-2l and h(x)=x^2+1. Find the value of each expression. (h∘g)(-1)
To find (h∘g)(-1), we need to first evaluate g(-1) and then use that result as the input for h.
g(x) is defined as 5x-2l, so g(-1) = 5(-1) - 2l = -7.
Now that we have g(-1) = -7, we can find (h∘g)(-1) by plugging it into h:
(h∘g)(-1) = h(g(-1)) = h(-7) = (-7)^2 + 1 = 50.
Therefore, (h∘g)(-1) = 50.
To find the value of the expression (h∘g)(-1), we need to substitute the value of -1 into the function g(x), and then substitute this resulting value into the function h(x).
Let's start with the function g(x):
g(x) = 5x - 2l
Substituting -1 into g(x):
g(-1) = 5(-1) - 2l
g(-1) = -5 - 2l
g(-1) = -5 - 2
g(-1) = -7
Now, we have the result from g(-1), which is -7. We can use this value to evaluate the function h(x).
h(x) = x^2 + 1
Substituting -7 into h(x):
h(-7) = (-7)^2 + 1
h(-7) = 49 + 1
h(-7) = 50
Therefore, the value of the expression (h∘g)(-1) is 50.