Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Allen draws one letter. Expressed as a fraction, decimal, and percentage, what is the probability that Allen will not select a consonant?
There are 8 letters in total, and 4 of them are consonants (S, L, C, T). Therefore, there are 8-4=4 vowels (E, E, E, D).
The probability of choosing a vowel is 4/8 or 1/2.
The probability of not choosing a consonant is the same as the probability of choosing a vowel, which is 1/2.
So the answer is:
1/2 = 0.5 = 50%
The sample space for a roll of two number cubes is shown in the table.
I'm sorry, there is no attached table or question to answer. Please provide more information.
To find the probability that Allen will not select a consonant, we need to first determine the total number of letters in the mix, as well as the number of consonants.
Total number of letters: Here, there are 8 letters: S, E, L, E, C, T, E, D.
Number of consonants: Consonants are all the letters except vowels (A, E, I, O, U). In this case, the consonants are S, L, C, T, and D. So, there are 5 consonants.
To calculate the probability, we divide the number of favorable outcomes (not selecting a consonant) by the total number of outcomes (selecting any letter).
Number of favorable outcomes: Since Allen should not select a consonant, the favorable outcomes are the vowels. In this case, the vowels are E and E. So, the number of favorable outcomes is 2.
Total number of outcomes: The total number of outcomes is the total number of letters in the mix, which is 8.
Now we can calculate the probability:
Probability = Number of favorable outcomes / Total number of outcomes
= 2 / 8
= 1/4
To express this as a decimal, divide the numerator by the denominator:
Probability = 0.25
To express this as a percentage, multiply the decimal by 100:
Probability = 0.25 * 100
= 25%
Therefore, the probability that Allen will not select a consonant is 1/4, 0.25, or 25%.