What are the first four terms of the sequence represented by the expression 3n+8 ?
When n=1, we have 3(1)+8=11 as the first term.
When n=2, we have 3(2)+8=14 as the second term.
When n=3, we have 3(3)+8=17 as the third term.
When n=4, we have 3(4)+8=20 as the fourth term.
Therefore, the first four terms of the sequence represented by the expression 3n+8 are:
11, 14, 17, 20.
To find the first four terms of the sequence represented by the expression 3n+8, you can substitute the first four positive integer values of n into the expression and simplify.
Let's calculate the values:
1. When n is 1: 3(1) + 8 = 3 + 8 = 11
2. When n is 2: 3(2) + 8 = 6 + 8 = 14
3. When n is 3: 3(3) + 8 = 9 + 8 = 17
4. When n is 4: 3(4) + 8 = 12 + 8 = 20
Therefore, the first four terms of the sequence represented by the expression 3n+8 are 11, 14, 17, and 20.