How many grams of iron can be made from the complete reaction of 21.4 grams of Fe2O3?
Fe2O3 + 3CO -----> 2Fe + 3CO2
a
0.150 grams
b
150 grams
c
15.0 grams
d
1.50 grams
The first step in solving this problem is to calculate the moles of Fe2O3 present:
moles of Fe2O3 = 21.4 g / 159.69 g/mol = 0.134 moles
Next, we need to determine which reactant is limiting, meaning it will be completely consumed in the reaction and determine the amount of product that can be formed. To do this, we can compare the moles of Fe2O3 to the moles of CO available for the reaction:
moles of CO = (3/1) * 0.134 moles = 0.402 moles
Since there are more moles of CO than are needed for the reaction, we know that Fe2O3 is the limiting reactant and all 0.134 moles will be used up. We can then calculate the moles of Fe that can be produced from the reaction:
moles of Fe = (2/1) * 0.134 moles = 0.268 moles
Finally, we use the molar mass of iron to convert the moles to grams:
mass of Fe = 0.268 moles * 55.85 g/mol = 15.0 grams
Therefore, the answer is (c) 15.0 grams.
To answer this question, you need to determine the molar mass of Fe2O3 and Fe.
The molar mass of Fe2O3 = (2 x molar mass of Fe) + (3 x molar mass of O)
= (2 x 55.845 g/mol) + (3 x 16.00 g/mol)
= 111.69 g/mol + 48.00 g/mol
= 159.69 g/mol
Now, you can use stoichiometry to calculate the amount of Fe that can be made from 21.4 grams of Fe2O3.
The balanced equation tells us that 1 mole of Fe2O3 reacts to form 2 moles of Fe.
Thus, the molar ratio is:
1 mole of Fe2O3 : 2 moles of Fe.
To calculate the moles of Fe2O3 given 21.4 grams, use the formula:
moles = mass / molar mass
moles of Fe2O3 = 21.4 g / 159.69 g/mol
moles of Fe2O3 = 0.134 moles
From the molar ratio, we know that 1 mole of Fe2O3 will produce 2 moles of Fe.
So, 0.134 moles of Fe2O3 will produce 2 x 0.134 moles of Fe.
Now, calculate the mass of Fe using the moles and molar mass of Fe:
mass of Fe = moles of Fe x molar mass of Fe
mass of Fe = (2 x 0.134) moles x 55.845 g/mol
mass of Fe = 18.844 g
Therefore, the answer is 18.844 grams of Fe can be made from the complete reaction of 21.4 grams of Fe2O3.
The correct option is d) 1.50 grams.