What mass of sucrose (C12H22O11) is needed to make 0.500 L of a 0.200 M solution?
(grams = M x gfm x M; sucrose = 342 g/mol)
First, we need to calculate the number of moles of sucrose needed to make the solution:
0.200 moles/L x 0.500 L = 0.100 moles
Next, we can use the formula grams = moles x gfm (molar mass) to calculate the mass of sucrose needed:
grams = 0.100 moles x 342 g/mol = 34.2 g
Therefore, 34.2 grams of sucrose is needed to make 0.500 L of a 0.200 M solution.
To calculate the mass of sucrose needed to make a 0.200 M solution in a 0.500 L volume, we can use the formula:
mass = M x V x gfm
Where:
M = molarity of the solution (in moles/L)
V = volume of the solution (in L)
gfm = molar mass of sucrose (in g/mol)
First, let's calculate the moles of sucrose:
moles = M x V
Moles = 0.200 M x 0.500 L
Moles = 0.100 moles
Now, we can calculate the mass of sucrose using the formula:
mass = moles x gfm
mass = 0.100 moles x 342 g/mol
mass = 34.2 grams
Therefore, 34.2 grams of sucrose is needed to make a 0.500 L of a 0.200 M solution.