How many moles are in 38.4 grams of ethane (C2H6)?
To calculate the number of moles in 38.4 grams of ethane (C2H6), we need to use the formula:
moles = mass/molar mass
The molar mass of ethane (C2H6) is:
2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol
Substituting the values, we get:
moles = 38.4 g/30.07 g/mol
moles = 1.28 mol
Therefore, there are 1.28 moles of ethane (C2H6) in 38.4 grams.
To determine the number of moles in 38.4 grams of ethane (C2H6), we need to use the molar mass of ethane.
The molar mass of carbon (C) is approximately 12.01 grams/mol, and the molar mass of hydrogen (H) is approximately 1.01 grams/mol.
Ethane (C2H6) contains 2 carbon atoms and 6 hydrogen atoms, so we can calculate its molar mass as follows:
Molar mass of C2H6 = (2 × molar mass of C) + (6 × molar mass of H)
= (2 × 12.01 g/mol) + (6 × 1.01 g/mol)
= 24.02 g/mol + 6.06 g/mol
= 30.08 g/mol
Now, we can use this molar mass to find the number of moles:
Number of moles = mass (in grams) / molar mass
= 38.4 g / 30.08 g/mol
= 1.277 mol
Therefore, there are approximately 1.277 moles in 38.4 grams of ethane (C2H6).