Determine the energy of electron of hydrogen atom at n=2
The energy of an electron in a hydrogen atom can be calculated using the formula:
E = -13.6/n^2 eV
where n is the principal quantum number. When n=2, we can substitute it into the above formula and get:
E = -13.6/2^2 = -3.4 eV
Therefore, the energy of the electron in a hydrogen atom at n=2 is -3.4 eV.
The energy of an electron in the hydrogen atom at a certain energy level is given by the formula:
E = -13.6 eV / n^2
Where E is the energy, -13.6 eV is a constant known as the ionization energy of the hydrogen atom, and n is the principal quantum number.
In this case, we are given that n = 2, so we can substitute it into the formula:
E = -13.6 eV / (2^2)
E = -13.6 eV / 4
Performing the calculation:
E = -3.4 eV
Therefore, the energy of the electron in the hydrogen atom at n=2 is -3.4 eV.