Find the Broglie wavelength of electron with a velocity of 10^5m/s
The formula for calculating the Broglie wavelength of a particle is:
λ = h/mv
where λ is the wavelength, h is Planck's constant (6.626 x 10^-34 J.s), m is the mass of the particle, and v is the velocity of the particle.
In this case, we are given the velocity of an electron, which has a mass of 9.109 x 10^-31 kg. Plugging in these values, we get:
λ = (6.626 x 10^-34 J.s)/(9.109 x 10^-31 kg x 10^5 m/s)
λ = 7.27 x 10^-11 m
Therefore, the Broglie wavelength of an electron with a velocity of 10^5m/s is approximately 7.27 x 10^-11 m.
To find the de Broglie wavelength of an electron, you can use the de Broglie equation:
wavelength = h / momentum
where h is the Planck's constant (6.626 x 10^(-34) Js) and momentum is the product of mass (m) and velocity (v):
momentum = mv
Given that the velocity of the electron is 10^5 m/s, we can find its de Broglie wavelength.
Step 1: Determine the mass of an electron
The mass of an electron is approximately 9.10938356 x 10^(-31) kg (kilograms).
Step 2: Calculate the momentum of the electron
momentum = mass x velocity
Substituting the values:
momentum = (9.10938356 x 10^(-31) kg) x (10^5 m/s)
Step 3: Calculate the de Broglie wavelength
wavelength = h / momentum
Substituting the values:
wavelength = (6.626 x 10^(-34) Js) / [(9.10938356 x 10^(-31) kg) x (10^5 m/s)]
Now, you can calculate the de Broglie wavelength of the electron by performing the calculation in step 3.