Identify the center and radius of a circle with equation (x-5)^2+(y+3)^2=25
The center of the circle is (5,-3) and the radius is 5.
This is because the equation of a circle with center (a,b) and radius r is given by (x-a)^2+(y-b)^2=r^2.
Comparing this to the given equation, we see that a=5, b=-3, and r=√25=5.
To identify the center and radius of the given circle with equation (x-5)^2+(y+3)^2=25, we can use the standard equation for a circle:
(x - h)^2 + (y - k)^2 = r^2
Comparing this equation to the given equation, we can see that the center of the circle is at the point (h, k) = (5, -3), and the radius of the circle is sqrt(r^2) = sqrt(25) = 5.
Therefore, the center of the circle is (5, -3), and the radius is 5.