An electrolytic decomposition reaction is a type of decomposition reaction in which the activation energy for decomposition is provided in the form of electrical energy. An example of an electrolytic decomposition reaction is the electrolysis of water shown below. If 18 g of water is subjected to an electrolytic decomposition reaction, what mass of oxygen will be produced?
Note: Balance the equation before solving the problem
H2O→H2+ O2
(Molar masss: O = 16 g/mol; H =1 g/mol)
The balanced equation for the electrolysis of water is:
2 H2O → 2 H2 + O2
From the balanced equation, we can see that for every 2 moles of water decomposed, 1 mole of oxygen is produced.
To find the mass of oxygen produced from 18 g of water, we need to first find the number of moles of water present:
18 g H2O x (1 mole H2O / 18 g H2O) = 1 mole H2O
So we have 1 mole of water, which means we can produce:
1 mole H2O x (1 mole O2 / 2 mole H2O) = 0.5 moles O2
Finally, we can calculate the mass of oxygen produced using its molar mass:
0.5 moles O2 x 16 g/mol = 8 g O2
Therefore, 8 g of oxygen will be produced from 18 g of water in an electrolytic decomposition reaction.
To find the mass of oxygen produced during the electrolysis of water, we need to use the balanced equation for the reaction and calculate the molar ratio.
The balanced equation for the electrolysis of water is:
2 H2O → 2 H2 + O2
According to the equation, for every 2 moles of water (H2O), 1 mole of oxygen (O2) is produced.
To calculate the moles of water, we can use the molar mass of water (H2O):
Molar mass of H2O = 2(1 g/mol) + 16 g/mol = 18 g/mol
Using the molar mass, we can calculate the moles of water:
Moles of H2O = Mass of H2O / Molar mass of H2O
Moles of H2O = 18 g / 18 g/mol = 1 mole
Now we can calculate the moles of oxygen produced:
Moles of O2 = Moles of H2O / Molar ratio
Moles of O2 = 1 mole / 2 = 0.5 moles
Finally, to calculate the mass of oxygen produced, we can use the molar mass of oxygen (O2):
Mass of O2 = Moles of O2 × Molar mass of O2
Mass of O2 = 0.5 moles × 32 g/mol = 16 g
Therefore, 16 grams of oxygen will be produced during the electrolysis of 18 grams of water.