Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Allen draws one letter. Expressed as a fraction, decimal, and percentage, what is the probability that Allen will not select a consonant?
A. three-eighths, 0.375, 37.5%
B. start fraction 3 over 5 end fraction, 0.6, 60%
C. start fraction 5 over 8 end fraction, 0.625, 62.5%
D. one-half, 0.5, 50%.
There are 8 letters in total. Out of these, only the letters S, L, T, and D are consonants. Therefore, there are 4 consonants and 4 vowels (E). The probability of Allen selecting a consonant is $\dfrac{4}{8} = \dfrac{1}{2}$ or 0.5 or 50\%. Therefore, the probability of Allen not selecting a consonant is $1 - \dfrac{1}{2} = \dfrac{1}{2}$ or 0.5 or 50\%.
Therefore, the answer is $\boxed{\textbf{(D) } \text{one-half, 0.5, 50\%}}$.
To find the probability that Allen will not select a consonant, we need to determine the number of consonants and the total number of letters in the group.
The given letters are S, E, L, E, C, T, E, and D.
Out of these letters, the vowels are E, E, and E. The consonants are S, L, C, T, and D.
The total number of letters in the group is 8, so the probability of not selecting a consonant is (number of vowels) / (total number of letters).
The number of vowels is 3 and the total number of letters is 8.
Therefore, the probability can be expressed as a fraction:
Probability = 3/8
To convert this fraction into a decimal, divide the numerator by the denominator:
Probability = 0.375
To convert this decimal into a percentage, multiply by 100:
Probability = 37.5%
Therefore, the answer is option A: three-eighths, 0.375, 37.5%.