Suggest the form of alanine (sidechain R = CH3) at low pH ~1. No stereochemistry is required for this answer.

At low pH (~1), alanine will be protonated and have a positive charge. The form of alanine would be NH3+ - CH(R) - COO-.

At low pH ~1, alanine (R = CH3) exists in its protonated form. The amino group (-NH2) of alanine will pick up a proton (H+) and become positively charged, forming an ammonium ion. Therefore, the form of alanine at low pH ~1 is CH3-CH(NH3+)-COOH.