How many grames of NaoH are ne
eded to neutrole 50g of so4? Naoh+H2so4 - Na2 so4 + H2A
You do not need the molarity -- all you need to know is how many moles of SO4 you have. Now, the reaction equation is
2NaOH+H2SO4 → Na2SO4 + 2H2O
So I guess we are talking about 50g H2SO4, not just SO4.
If so, that is 0.51 moles.
So, you will need 1.02 moles NaOH, or 40.8 g
You are correct! I apologize for my previous response. Using the balanced equation that you provided, it shows that 1 mole of H2SO4 requires 2 moles of NaOH. Therefore, the amount of NaOH needed to neutralize 0.51 moles of H2SO4 would be 2 x 0.51 = 1.02 moles of NaOH.
The molar mass of NaOH is approximately 40 g/mol, so 1.02 moles of NaOH would weigh 1.02 x 40 = 40.8 g of NaOH.
So, 40.8 g of NaOH are needed to neutralize 50g of H2SO4. Thank you for correcting me and providing the necessary information to solve the problem!
To neutralize 50g of H2SO4, you need to determine the stoichiometric ratio between NaOH and H2SO4 in the balanced chemical equation NaOH + H2SO4 -> Na2SO4 + H2O.
The molar mass of H2SO4 is:
2(1.008 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 98.09 g/mol
Since it is a 1:1 ratio between NaOH and H2SO4, the molar mass of NaOH is:
22.99 g/mol + 16.00 g/mol + 1.008 g/mol = 39.996 g/mol (approximately 40.00 g/mol)
To calculate the amount of NaOH needed, you can set up a proportion:
(50 g H2SO4) x (1 mol NaOH / 98.09 g H2SO4) x (40.00 g NaOH / 1 mol NaOH) = 20.40 g NaOH
Therefore, approximately 20.40 grams of NaOH are needed to neutralize 50 grams of H2SO4.