The radius of a circle is not greater than 3m.
What can be said about it a. It's circumference. b. It's area? Give any inequalities in terms of π
a. The circumference of the circle is less than or equal to 6π meters (C ≤ 6π).
b. The area of the circle is less than or equal to 9π square meters (A ≤ 9π).
if x= 2a+3/3a-2, express x-1/2x+1 in terms of a
a. The circumference of a circle is given by the formula C=2πr, where r is the radius of the circle. Based on the given information that the radius is not greater than 3m, we can say that the circumference of the circle is not greater than 2π(3)m = 6πm.
So, the inequality for the circumference would be: C ≤ 6πm.
b. The area of a circle is given by the formula A=πr^2, where r is the radius of the circle. Similarly, based on the given information, we can say that the area of the circle is not greater than π(3m)^2 = 9πm^2.
So, the inequality for the area would be: A ≤ 9πm^2.
To determine what can be said about the circumference and area of a circle with a radius not greater than 3m, we can use the formulas for both.
a. Circumference: The formula for the circumference of a circle is C = 2πr, where C represents the circumference and r represents the radius.
Since the question states that the radius is not greater than 3m, we can write this as r ≤ 3m. Plugging this into the formula, we have C ≤ 2π(3m) = 6πm.
Therefore, we can say that the circumference of the circle is not greater than 6πm.
b. Area: The formula for the area of a circle is A = πr^2, where A represents the area and r represents the radius.
Using the same information that the radius is not greater than 3m, we can write this as r ≤ 3m. Plugging this into the formula, we have A ≤ π(3m)^2 = 9πm^2.
Therefore, we can say that the area of the circle is not greater than 9πm^2.