Percentage composition of Mg(CN)2
To find the percentage composition of Mg(CN)2, we need to calculate the total molar mass of the compound and the contribution of each element to that mass.
The molar mass of Mg(CN)2 can be calculated as follows:
Mg: 1 x 24.31 g/mol = 24.31 g/mol
C: 2 x 12.01 g/mol = 24.02 g/mol
N: 2 x 14.01 g/mol = 28.02 g/mol
Total molar mass = 24.31 + 24.02 + 28.02 = 76.35 g/mol
To find the percentage composition of each element in Mg(CN)2, we calculate the contribution of each element to the total molar mass:
Mg: (24.31 g/mol / 76.35 g/mol) x 100% = 31.86%
C: (24.02 g/mol / 76.35 g/mol) x 100% = 31.49%
N: (28.02 g/mol / 76.35 g/mol) x 100% = 36.65%
Therefore, the percentage composition of Mg(CN)2 is as follows:
- Magnesium (Mg): 31.86%
- Carbon (C): 31.49%
- Nitrogen (N): 36.65%
To determine the percentage composition of Mg(CN)2, we need to know the molar masses of each element in the compound.
The molar mass of Mg (magnesium) is approximately 24.31 g/mol.
The molar mass of C (carbon) is approximately 12.01 g/mol.
The molar mass of N (nitrogen) is approximately 14.01 g/mol.
Now, let's calculate the molar mass of Mg(CN)2:
Molar mass of Mg(CN)2 = (Molar mass of Mg) + 2*(Molar mass of C) + 2*(Molar mass of N)
Plugging in the values:
Molar mass of Mg(CN)2 = 24.31 + 2*(12.01) + 2*(14.01) = 24.31 + 24.02 + 28.02 = 76.35 g/mol
The percentage composition of Mg(CN)2 can be calculated by dividing the molar mass of each element by the molar mass of the compound.
Percentage of Mg = (Molar mass of Mg / Molar mass of Mg(CN)2) * 100
= (24.31 / 76.35) * 100 ≈ 31.86%
Percentage of C = (2 * Molar mass of C / Molar mass of Mg(CN)2) * 100
= (2 * 12.01 / 76.35) * 100 ≈ 31.33%
Percentage of N = (2 * Molar mass of N / Molar mass of Mg(CN)2) * 100
= (2 * 14.01 / 76.35) * 100 ≈ 36.81%
Therefore, the percentage composition of Mg(CN)2 is approximately:
31.86% magnesium, 31.33% carbon, and 36.81% nitrogen.