(2y-1)(4y-3)
A) -2y+3
B) 8y2-10y-3
C) 8y^2-10y+3
D) 8y^2-2y+3
The correct answer is D) 8y^2-2y+3.
To expand the given expression using the FOIL method (First Outer Inner Last), we can follow these steps:
(2y-1)(4y-3)
= 2y(4y) + 2y(-3) - 1(4y) - 1(-3)
= 8y^2 - 6y - 4y + 3
= 8y^2 - 10y + 3
Therefore, the answer is D) 8y^2-2y+3.
To expand the expression (2y-1)(4y-3), we can use the distributive property.
First, we multiply the first terms of each binomial:
(2y)(4y) = 8y^2
Next, we multiply the outer terms of each binomial:
(2y)(-3) = -6y
Then, we multiply the inner terms of each binomial:
(-1)(4y) = -4y
Finally, we multiply the last terms of each binomial:
(-1)(-3) = 3
Adding up all the resulting terms:
8y^2 - 6y - 4y + 3
Combining like terms:
8y^2 - 10y + 3
Therefore, the correct answer is C) 8y^2 - 10y + 3.