predict the geometries of the complexes from these reactions:
1- [pt(NO2)cl3)]2- + NH3 --> [pt(NO2)(NH3)cl2]-1 +cl-
2-cis-[pt(RNH2)2(NH3)(NO2)]+1 + cl- --> Pt(RNH2)(NH3)(NO2)Cl + RNH2
You have posted this same question numerous times. Unfortunately, you haven't clarified the question. Exactly which compounds do you want the geometry. You have four listed; is it the first and third, all four, or what?
From the literature I can find, most Pt complexes are square planar. The first compound listed for #2 MUST be square planar because that's the only four-coordinate complex that will give cis and trans isomers (sp3 tetrahedral won't do it). The first compound of #1 could be sp3 hybridized (and tetrahedral); however, since most Pt complexes with coordination 4 are square planar, I think this would be square planar also. My best advice is to go to your school library and look under books with Pt chemistry and coordination chemistry. Sorry I'm not more help.
To predict the geometries of the complexes from the given reactions, we need to first determine the electron pair arrangements and bond angles around the central metal atom. This can be done by applying the VSEPR (Valence Shell Electron Pair Repulsion) theory.
1. [Pt(NO2)Cl3)]2- + NH3 --> [Pt(NO2)(NH3)Cl2]-1 + Cl-
For the reactant complex [Pt(NO2)Cl3)]2-, the central platinum (Pt) atom is coordinated with three chloride (Cl) ions and one nitro (NO2) group. The coordination number of Pt is 4.
When NH3 (ammonia) reacts with this complex, it replaces one of the chloride ions, resulting in the product complex [Pt(NO2)(NH3)Cl2]-1. Here, the central Pt atom is coordinated with one nitro group (NO2), two ammonia molecules (NH3), and two chloride ions (Cl-).
To determine the geometry of the product complex, we count the total number of electron pairs around the central Pt atom. There are two electron pairs from the nitro group (NO2), two from the ammonia molecules (NH3), and two from the chloride ions (Cl-). Therefore, there are six electron pairs in total.
Using the VSEPR theory, we can predict that the electron pairs will arrange themselves in an octahedral geometry around the Pt atom. This means that the Pt atom will have a coordination number of 6 and the resulting complex will have an octahedral geometry.
2. cis-[Pt(RNH2)2(NH3)(NO2)]+1 + Cl- --> Pt(RNH2)(NH3)(NO2)Cl + RNH2
For the reactant complex cis-[Pt(RNH2)2(NH3)(NO2)]+1, the central platinum (Pt) atom is coordinated with two amine (RNH2) ligands, one ammonia (NH3) molecule, and one nitro (NO2) group. The coordination number of Pt is 4.
When Cl- (chloride ion) reacts with this complex, it replaces the ammonia molecule, resulting in the product complex Pt(RNH2)(NH3)(NO2)Cl. Here, the central Pt atom is coordinated with one amine ligand (RNH2), one ammonia molecule (NH3), one nitro group (NO2), and one chloride ion (Cl-).
To determine the geometry of the product complex, we count the total number of electron pairs around the central Pt atom. There are two electron pairs from the amine ligands (RNH2), two from the ammonia molecule (NH3), one from the nitro group (NO2), and one from the chloride ion (Cl-). Therefore, there are six electron pairs in total.
Using the VSEPR theory, we can predict that the electron pairs will arrange themselves in an octahedral geometry around the Pt atom. This means that the Pt atom will have a coordination number of 6 and the resulting complex will have an octahedral geometry.