In a diagram of a landscape plan, the scale is 1 cm = 10
ft. In the diagram, the trees are 3.7 cm apart. How far apart should the actual trees be planted?
(1 point)
O 0.37 ft.
O 37 cm
O 37 ft.
O 370 ft.
0.37 ft.
What is the area of triangle APQR to the nearest tenth of a square meter? Drawing is not to
scale.
18 m
25
8 m
(1 point)
O 60.8 m²
O 65.3 m²
O30.4 m²
O 32.7 m²
We can use the formula for the area of a triangle:
(area) = 1/2 (base)(height)
To find the base and height, we can use the Pythagorean theorem:
(base)^2 + (height)^2 = (hypotenuse)^2
In this case, we can use 18 m as the hypotenuse.
First, we can find the length of segment PQ:
PQ^2 = 18^2 - 8^2 = 256
PQ = 16
Now we can use PQ as the base and find the height:
(height)^2 = 18^2 - 16^2 = 68
height ≈ 8.25
Then we can find the area:
(area) = 1/2 (16)(8.25) ≈ 66.0
Rounding to the nearest tenth, the area of triangle APQR is 66.0 m².
Answer: O 65.3 m²
To determine how far apart the actual trees should be planted, we need to convert the distance on the diagram (3.7 cm) to the actual distance using the given scale (1 cm = 10 ft).
First, we can calculate the actual distance using the formula:
actual distance = distance on diagram × scale
Plugging in the given values:
actual distance = 3.7 cm × 10 ft/cm
Multiply 3.7 cm by 10 ft/cm:
actual distance = 37 ft
Therefore, the actual trees should be planted 37 ft apart.
The correct answer is: O 37 ft.