At a school assembly, 3 out of the first 10 students were wearing spirit wear. Based on this information, if 400 students were at the assembly, then how many students could be expected to have on spirit wear? bot
To solve this problem, we can set up a proportion:
3/10 = x/400
To solve for x, we can cross-multiply:
10x = 3 * 400
10x = 1200
x = 120
Therefore, we can expect 120 students to have on spirit wear at the assembly.
Two coins are flipped. What is the probability that both coins land on heads? bot
To solve this problem we need to consider the number of possible outcomes and the number of favorable outcomes.
There are four possible outcomes when two coins are flipped: HH, HT, TH, and TT. Only one of these outcomes is a favorable outcome for both coins landing on heads. Therefore, the probability that both coins land on heads is:
1 favorable outcome / 4 possible outcomes = 1/4 or 0.25
So the probability that both coins land on heads is 0.25 or 25%.
Daniel is selecting a sock from his drawer at random. If Daniel does this 60 times, what is reasonable prediction for the number of times he will get a striped sock? there is 2 striped socks in the drawer. bot
The probability that Daniel selects a striped sock from his drawer is 2 out of the total number of socks in his drawer. Let's assume there are a total of S socks in his drawer. Then, the probability of selecting a striped sock is:
P(striped sock) = 2/S
If Daniel selects a sock 60 times, we can use this probability to make a reasonable prediction for the number of times he will get a striped sock using the expected value formula:
E = n * P(event)
where E is the expected value, n is the number of times the event occurs, and P(event) is the probability of the event.
In this case, the number of times the event occurs is the number of times Daniel selects a sock, which is 60.
So, the expected number of times he will get a striped sock is:
E = 60 * P(striped sock)
E = 60 * (2/S)
E = 120/S
Since we do not know the total number of socks in the drawer, we cannot determine the exact expected value. However, we can say that if Daniel has a large drawer of socks, then a reasonable prediction for the number of times he will get a striped sock is likely to be around 120 divided by the total number of socks in the drawer.
The list below shows the different pizzas sold by noon at a local pizza shop.
Pepperoni: 11
Supreme: 7
Cheese: 6
Hawaiian: 3
Based on these results, if 189 pizzas were sold by the end of the day, how many pizzas could be expected to be cheese? bot
To answer this question, we need to find the proportion of pizzas sold that were cheese and use it to estimate the number of cheese pizzas sold out of the total of 189 pizzas.
The total number of pizzas sold by noon is:
11 + 7 + 6 + 3 = 27
To find the proportion of pizzas sold that were cheese, we divide the number of cheese pizzas by the total number of pizzas sold:
6/27 = 0.22
So, about 22% of the pizzas sold by noon were cheese pizzas. To estimate the number of cheese pizzas sold out of the total of 189 pizzas sold by the end of the day, we multiply the total number of pizzas sold by this proportion:
0.22 x 189 = 41.58
Rounding to the nearest whole number, we can expect about 42 cheese pizzas to be sold by the end of the day.