In a store window, there was a box of berries having a total weight of 200 kg. The berries were 99% water, by weight. After two days in the sun, the water content of the berries was only 90%, by weight. What was the total weight of the berries after two days, in kg?

Question

In a store window, there was a box of berries having a total weight of 200 kg. The berries were 99% water, by weight. After two days in the sun, the water content of the berries was only 90%, by weight. What was the total weight of the berries after two days, in kg?

Answer 1

If the berries were 99% water, then 1% of the weight was from non-water content.

Let's call the non-water weight "x."

1% of the weight is x:

0.01(weight) = x

Multiply both sides by 100 to solve for weight:

weight = 100x

If the berries originally weighed 200 kg, then the weight of non-water content was:

weight = 100x = 200 kg

x = 2 kg

So the original 200 kg was made up of 2 kg of non-water content and 198 kg of water.

After two days in the sun, the water content decreased to 90%. Now, 10% of the weight is from non-water content.

Let's call the new weight "w."

10% of the weight is x:

0.1(w) = x

We know that the non-water content stays the same, so:

2 kg = x

Substitute this value of x into the equation for weight:

w = 100x/0.1 = 100(2)/0.1 = 2000 kg

Therefore, the total weight of the berries after two days in the sun was 2000 kg.

Answer 2

To find the total weight of the berries after two days, we need to determine the weight of the water and the weight of the remaining berry solids.

Let's start by finding the weight of the water in the berries initially:

Water content = 99% = 99/100 = 0.99
Weight of water = Water content * Total weight of berries = 0.99 * 200 kg = 198 kg

Now, let's find the weight of the remaining berry solids after two days:

Water content after two days = 90% = 90/100 = 0.9
Weight of water after two days = Water content after two days * Total weight of berries after two days

Since the weight of water and the weight of berry solids add up to the total weight of berries, we can calculate the weight of the solids as follows:

Weight of berry solids after two days = Total weight of berries after two days - Weight of water after two days

Let's substitute the given values:

Weight of water after two days = 0.9 * Total weight of berries after two days
Weight of berry solids after two days = Total weight of berries after two days - Weight of water after two days

Since the weight of water after two days is 198 kg, we can now calculate the weight of the berry solids:

Weight of berry solids after two days = Total weight of berries after two days - 198 kg

Unfortunately, we do not have enough information to calculate the total weight of the berries after two days. We can only conclude that:

Total weight of berries after two days = Weight of berry solids after two days + Weight of water after two days

Please provide additional information if available, or rephrase the question, and I will be happy to assist you further.