Divide.
(20x^2-12x+8) divide (2x-8)
To divide (20x^2-12x+8) by (2x-8), we can use long division:
10x + 7
-----------------
2x - 8 | 20x^2 - 12x + 8
- (20x^2 - 80x)
---------------
68x + 8
- (68x - 272)
-----------
280
Therefore, the quotient is 10x + 7 and the remainder is 280.
To divide (20x^2 - 12x + 8) by (2x - 8), we can use long division. Here are the steps:
Step 1: Set up the division, with the dividend on the left and the divisor on the outside.
___________________________
(2x - 8) | (20x^2 - 12x + 8)
Step 2: Divide the first term of the dividend (20x^2) by the first term of the divisor (2x), and write the result above the line.
___________________________
(2x - 8) | (20x^2 - 12x + 8)
(10x)
Step 3: Multiply the divisor (2x - 8) by the result obtained in the previous step (10x), and write the result below the dividend term it multiplied with.
___________________________
(2x - 8) | (20x^2 - 12x + 8)
(10x)
- (20x - 80)
Step 4: Subtract the result obtained in the previous step from the original dividend.
___________________________
(2x - 8) | (20x^2 - 12x + 8)
(10x)
- (20x - 80)
_______________
(-92x + 88)
Step 5: Bring down the next term from the dividend.
___________________________
(2x - 8) | (20x^2 - 12x + 8)
(10x)
- (20x - 80)
_______________
(-92x + 88)
(-92x + 368)
Step 6: Divide the first term of the new dividend (-92x) by the first term of the divisor (2x), and write the result above the line.
___________________________
(2x - 8) | (20x^2 - 12x + 8)
(10x - 48)
- (20x - 80)
_______________
(-92x + 88)
(-92x + 368)
_______________
(-280)
Step 7: Check if the new dividend term (in this case, -280) is divisible by the first term of the divisor (2x). Since it's not, we have reached the end of the process.
So, the result of dividing (20x^2 - 12x + 8) by (2x - 8) is:
Quotient = 10x - 48
Remainder = -280