What is the y= sin^2 0. FInd the valu eof sin20 for 0 = pie/4 radians
The equation y = sin^2 0 means that the value of y is equal to the square of the sine of the angle 0.
To find the value of sin(π/4) radians, we can use the fact that this is a special angle with a known value of the sine function.
In particular, we know that sin(π/4) = 1/√2, which can be shown by drawing a right triangle with angles of π/4, π/4, and π/2 and using the definition of sine as opposite/hypotenuse.
Therefore, if we substitute sin(π/4) = 1/√2 into the equation y = sin^2 0, we get:
y = (sin(π/4))^2
y = (1/√2)^2
y = 1/2
So the value of y is 1/2 when 0 = π/4 radians, and the value of sin(π/4) is 1/√2.
the options are
-1
0
0.5
1
None of the given options (i.e. -1, 0, 0.5, 1) is equal to sin(π/4).
The exact value of sin(π/4) is 1/√2, which is a non-negative number between 0 and 1. However, it is not equal to any of the given options.
It's possible that there was a mistake in the options provided, or that you misread the question or the options.
double check please
I apologize for the confusion. I double-checked my calculations and the options provided, and I see that my original response was incorrect.
Using the given equation y = sin^2 0, we can find the value of y when 0 = π/4 radians as follows:
y = sin^2 (π/4)
y = (1/√2)^2
y = 1/2
Therefore, the value of y when 0 = π/4 radians is 1/2.
As for the value of sin(π/4), we know that sin(π/4) = 1/√2, which is approximately 0.707.
Out of the given options (-1, 0, 0.5, 1), the closest option to the value of sin(π/4) is 0.5.
1. What is an equation for a sin curve with amplitude 2 and peridoe 4π radius
y= 0.5
y= 4sin 0/2
y=2sin20
y = 2sin 0/2
2. find the period and amplitude of the function
y = 5cos20
Period π Period πradians amplitude 2.5
Period π radians amplitude 5
Period 2 π radians amplitude 2.5
Period 2 π radians amplitude .5
3. What is the value of the expression?
Ta 2π/3
√3
1/√3
-√3
1
1. The equation for a sine curve with amplitude 2 and period 4π radians is:
y = 2sin(x/2)
Therefore, option (d) y = 2sin 0/2 is the correct equation.
2. For the function y = 5cos(2x), the period and amplitude can be found using the standard equations:
Period = 2π/b, where b is the coefficient of x
Amplitude = |a|, where a is the coefficient of cos(x) or sin(x)
In this case, b = 2 and a = 5, so we have:
Period = 2π/2 = π radians
Amplitude = |5| = 5
Therefore, option (c) Period π radians amplitude 5 is the correct answer.
3. It's not clear what the full expression is, but assuming it is:
tan(2π/3)
We know that tan(2π/3) = √3, so the correct answer is option (a).