The diameter of four different types of atoms are given below.
Atom A:1.35x10^-7 mm; Atom B:1.80x10^-7 mm; Atom C:6.00x10^-8 mm; Atom D:2.50x10^-9 mm
What is the order of these atoms from largest to smallest?
The order of these atoms from largest to smallest is:
Atom B > Atom A > Atom C > Atom D
To see this, we can convert all of the diameters to meters for easier comparison:
Atom A: 1.35 x 10^-7 mm = 1.35 x 10^-10 m
Atom B: 1.80 x 10^-7 mm = 1.80 x 10^-10 m
Atom C: 6.00 x 10^-8 mm = 6.00 x 10^-11 m
Atom D: 2.50 x 10^-9 mm = 2.50 x 10^-12 m
We can see that Atom B has the largest diameter, followed by Atom A, then Atom C, and finally Atom D with the smallest diameter.
To find the order of these atoms from largest to smallest, we will compare their diameters.
The given diameters are:
Atom A: 1.35x10^-7 mm
Atom B: 1.80x10^-7 mm
Atom C: 6.00x10^-8 mm
Atom D: 2.50x10^-9 mm
We can compare the diameters by converting all the values into the same unit. Let's convert them into meters:
1 mm = 10^-3 m
Atom A: 1.35x10^-7 mm = 1.35x10^-10 m
Atom B: 1.80x10^-7 mm = 1.80x10^-10 m
Atom C: 6.00x10^-8 mm = 6.00x10^-11 m
Atom D: 2.50x10^-9 mm = 2.50x10^-12 m
Now, we can compare the diameters:
Atom D: 2.50x10^-12 m (smallest)
Atom C: 6.00x10^-11 m
Atom A: 1.35x10^-10 m
Atom B: 1.80x10^-10 m (largest)
Therefore, the correct order of the atoms from largest to smallest is: B, A, C, D.