A puck is sliding along a frictionless surface at constant velocity.
Which of the following choices correctly models the forces acting on the puck?
Responses
A puck with two equal opposing forces. Normal force (surface on puck) points straight up, and gravitational force (Earth on puck) points straight down.
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Cline, Dusty/Shutterstock
Image with alt text: A puck with two equal opposing forces. Normal force (surface on puck) points straight up, and gravitational force (Earth on puck) points straight down. Arrows and labels added by FlipSwitch. Cline, Dusty/Shutterstock
A puck with three force vectors. Two are equal opposing forces: gravitational (Earth on puck) straight down, and normal force (surface on puck) straight up. An equal force of initial push (person on puck) points to the right.
Arrows and labels added by FlipSwitch.
Cline, Dusty/Shutterstock
Image with alt text: A puck with three force vectors. Two are equal opposing forces: gravitational (Earth on puck) straight down, and normal force (surface on puck) straight up. An equal force of initial push (person on puck) points to the right. Arrows and labels added by FlipSwitch. Cline, Dusty/Shutterstock
A puck with two equal force vectors: gravitational force (Earth on puck) straight down, and initial push (person on puck) to the right.
Arrows and labels added by FlipSwitch.
Cline, Dusty/Shutterstock
Image with alt text: A puck with two equal force vectors: gravitational force (Earth on puck) straight down, and initial push (person on puck) to the right. Arrows and labels added by FlipSwitch. Cline, Dusty/Shutterstock
A puck with one force vector to the right: initial push (person on puck).
C: A puck with two equal opposing forces: gravitational force (Earth on puck) straight down, and normal force (surface on puck) straight up.
do u mean a?
No, I mean C. The correct choice is a puck with two equal force vectors: gravitational force (Earth on puck) straight down, and initial push (person on puck) to the right. This accurately models the forces acting on the puck as it slides along a frictionless surface at constant velocity, because once the puck is moving at a constant velocity, the only force acting on it is the initial push. The gravitational force is balanced by the normal force, which is equal in magnitude and opposite in direction to the gravitational force.
u said it wrong at first
I apologize for the mistake in my initial response. Thank you for bringing it to my attention. To clarify, choice C accurately models the forces acting on the puck as it slides along a frictionless surface at constant velocity, with two equal force vectors: gravitational force (Earth on puck) straight down, and initial push (person on puck) to the right.
The correct choice is:
A puck with two equal opposing forces. Normal force (surface on puck) points straight up, and gravitational force (Earth on puck) points straight down.
The correct choice is the third option: A puck with two equal force vectors: gravitational force (Earth on puck) straight down, and initial push (person on puck) to the right.
To understand why this is the correct choice, let's analyze the forces acting on the puck. A puck that is sliding along a frictionless surface at a constant velocity experiences a balance of forces, meaning the net force acting on it is zero.
The first force acting on the puck is the gravitational force, which always points straight down towards the center of the Earth. This force is equal in magnitude to the weight of the puck.
The second force acting on the puck is the initial push given by the person. Since the puck is moving at a constant velocity, there must be an equal and opposite force to counteract any external forces. In this case, the initial push provides the necessary force to counteract the opposing force of gravity and maintain a constant velocity.
Therefore, the correct representation would be a puck with two equal force vectors: gravitational force (Earth on puck) straight down, and initial push (person on puck) to the right.