Match the graph with it's corresponding equation
A coordinate plane with a parabola graphed that opens up. The y-intercept is (0, negative 4) and the x-intercepts are between 0 and 1 and between negative 2 and negative 1.
A. y = 2x²
B. y = –2x² + 2
C. y = 2x²
D. y = 3x² – 4
really? for your answer, the y-intercept is (0,2) and it opens downward.
The only possible choice is D, but the roots are wrong, at ±1.15
Apologies, I made a mistake. The correct answer is:
D. y = 3x² - 4
The graph described is a parabola that opens up, with a y-intercept at (0, -4) and x-intercepts between 0 and 1 and between -2 and -1.
Given the information, we can eliminate options B and D since their leading coefficients are not 2.
To determine whether the equation is y = 2x² or y = -2x² + 2, we can compare the y-intercept.
Option A and C both have a y-intercept of (0, -4).
Let's now compare the x-intercepts. The x-intercepts are between 0 and 1 and between -2 and -1.
For y = 2x², the x-intercepts are x = 0 and x = ± (√2/2), which are indeed between 0 and 1, and there are no x-intercepts between -2 and -1.
Therefore, the graph matches with Option A: y = 2x².