Use the following table and spinner to answer the question. The table summarizes the results of spinning the spinner shown. Color red blue green yellow Number of times spun 6 5 3 4 What is the experimental probability of the spinner landing on red? A. B. C.
A. $\frac{6}{18}$ or $\frac{1}{3}$
Use the following table and spinner to answer the question. The table summarizes the results of spinning the spinner shown. Color red blue green yellow Number of times spun 6 5 3 4 What is the experimental probability of the spinner landing on red? A. 1/2 B. 1/3 C. 1/4
B. 1/3
Use the following table and spinner to answer the question.
The table summarizes the results of spinning the spinner shown.
The image shows a spinning wheel with 2 blue spaces, 2 yellow spaces, 2 green spaces, and 2 red spaces. One of the yellow spaces has an arrow.
Color
red
blue
green
yellow
Number of times spun
6
5
3
4
What is the theoretical probability of the spinner landing on red?
A. 1/2
B. 1/3
C. 1/4
B. 1/4
Use the following table and spinner to answer the question.
The table summarizes the results of spinning the spinner shown.
The image shows a spinning wheel with 2 blue spaces, 2 yellow spaces, 2 green spaces, and 2 red spaces. One of the yellow spaces has an arrow.
Color
red
blue
green
yellow
Number of times spun
6
5
3
4
What is the theoretical probability of the spinner landing on red?
A. 1/2
B. 1/3
C. 1/4
C. 1/4
Two coins were tossed 10 times. The results are shown in the table below.
result tableThe first column has the word Toss in the 1st Row and the word Results in the second row. The second column has the number 1 in the 1st Row and the letters H H in the 2nd Row. The third column has the number 2 in the 1st Row and the letters T T in the 2nd Row. The fourth column has the number 3 in the 1st Row and the letters H T in the 2nd Row. The fifth column has the number 4 in the 1st Row and the letters T H in the 2nd Row. The sixth column has the number 5 in the 1st Row and the letters H T in the 2nd Row. The seventh column has the number 6 in the 1st Row and the letters H H in the 2nd Row. The eighth column has the number 7 in the 1st Row and the letters T H in the 2nd Row. The ninth column has the number 8 in the 1st Row and the letters T T in the 2nd Row. The tenth column has the number 9 in the 1st Row and the letters T H in the 2nd Row. The eleventh column has the number 10 in the 1st Row and the letters H T in the 2nd Row.
What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
A. 0.8
B. 0.2
C. 0.6
A. 0.8
Two coins were tossed 10 times. The results are shown in the table below.
result tableThe first column has the word Toss in the 1st Row and the word Results in the second row. The second column has the number 1 in the 1st Row and the letters H H in the 2nd Row. The third column has the number 2 in the 1st Row and the letters T T in the 2nd Row. The fourth column has the number 3 in the 1st Row and the letters H T in the 2nd Row. The fifth column has the number 4 in the 1st Row and the letters T H in the 2nd Row. The sixth column has the number 5 in the 1st Row and the letters H T in the 2nd Row. The seventh column has the number 6 in the 1st Row and the letters H H in the 2nd Row. The eighth column has the number 7 in the 1st Row and the letters T H in the 2nd Row. The ninth column has the number 8 in the 1st Row and the letters T T in the 2nd Row. The tenth column has the number 9 in the 1st Row and the letters T H in the 2nd Row. The eleventh column has the number 10 in the 1st Row and the letters H T in the 2nd Row.
Make a tree diagram for two coins that are tossed. Find the theoretical probability that at least one coin is heads. Express the probability as a decimal.
A. 0.5
B. 0.75
C. 0.8
To construct the tree diagram, start with the first coin and draw two branches for each possible outcome (heads and tails). Then, for each of those branches, draw two additional branches representing the possible outcomes for the second coin (heads and tails).
The tree diagram will have four final branches: HH, HT, TH, and TT.
Out of these four outcomes, three (HH, HT, and TH) have at least one head, so the theoretical probability of getting at least one head is $\frac{3}{4}$ or 0.75.
Therefore, the answer is (B) 0.75.
Use the following table to answer question 5.
A number cube is rolled 100 times. The results are shown in the table below.
result table
Outcome 1 2 3 4 5 6
Number of Times Rolled 22 18 9 11 19 21
Find the experimental probability, and express it as a percent.
P(even) = ?
A. 50%
B. 40%
C. 29%
To find the experimental probability of rolling an even number, we need to add the frequencies of rolling 2, 4, and 6 (because those are the even possible outcomes), and divide by the total number of rolls:
Experimental probability of rolling an even number = $\frac{18+11+21}{100} = \frac{50}{100} = 0.5$
To express this as a percent, we multiply by 100:
Experimental probability of rolling an even number = 50%
Therefore, the answer is (A) 50%.
How does the experimental probability you found in question 5 compare to the theoretical probability of rolling an even number?
A. The theoretical probability is 10% greater than the experimental probability.
B. The experimental probability is 10% greater than the theoretical probability.
C. The theoretical probability is equal to the experimental probability.
C. The theoretical probability is equal to the experimental probability.
In this case, the theoretical probability of rolling an even number is $\frac{3}{6}$ or $\frac{1}{2}$, which is the same as the experimental probability we found in question 5. Therefore, the theoretical probability is equal to the experimental probability.
Multiple Choice
The table shows the results of spinning a four-colored spinner 50 times. Find the experimental probability and express it as a decimal.
P(not blue) = ?
A two row by five column table is shown. The first row is titled 'Color' and contains 'red,' 'blue,' 'green,' and 'yellow' from left to right. The second row is titled 'Number-sign of times spun' and contains 20, 10, 9, and 11 from left to right.
A. 0.1
B. 0.4
C. 0.8
D. 0.2
To find the experimental probability of not getting blue, we need to add the frequencies of spinning red, green, and yellow, and divide by the total number of spins:
Experimental probability of not getting blue = $\frac{20+9+11}{50} = \frac{40}{50} = 0.8$
Therefore, the answer is (C) 0.8.
You roll a number cube 20 times. It lands on 2 five times. What is the experimental probability of rolling a 2?
A. 40%
B. 10%
C. 25%
D. 17%
To find the experimental probability of rolling a 2, we need to divide the number of times the cube landed on 2 (5) by the total number of rolls (20):
Experimental probability of rolling a 2 = $\frac{5}{20} = 0.25$
To express this as a percentage, we multiply by 100:
Experimental probability of rolling a 2 = 25%
Therefore, the answer is (C) 25%.
The table below shows the results of flipping two coins. How does the experimental probability of getting HH compare to the theoretical probability of getting HH?
A two row by five column table is shown. The first row is titled 'Outcome' and contains 'upper H upper H,' 'upper H upper T,' 'upper T upper H,' and 'upper T upper T' from left to right. The second row is titled 'Number of times tossed' and contains 28, 22, 34, and 16 from left to right.
A. The experimental probability is 3% greater than the theoretical probability.
B. The theoretical probability is 3% greater than the experimental probability.
C. The experimental probability is equal to the theoretical probability.
D. The experimental probability is 7% greater than the theoretical probability.
To compare the experimental and theoretical probabilities of getting HH, we need to first find out the theoretical probability. When flipping two coins, there are four possible outcomes and only one of them is HH, so the theoretical probability of getting HH is $\frac{1}{4}$ or 0.25.
To find the experimental probability, we add up the frequencies of getting HH and divide by the total number of flips:
Experimental probability of getting HH = $\frac{28}{100} = 0.28$
To compare the two probabilities, we can find the difference between the experimental and theoretical probabilities as a percentage of the theoretical probability:
$\frac{0.28 - 0.25}{0.25} \times 100\% \approx 12\%$
Since the difference between the two probabilities is positive, we know that the experimental probability is greater than the theoretical probability. The answer option that is closest to our calculation is (D) The experimental probability is 7% greater than the theoretical probability.
A baseball player gets on base 7 times and strikes out 5 times during a tournament. What is the experimental probability of the player getting on base?
A. 5/7
B. 7/12
C. 5/12
D. 7/10
To find the experimental probability of the player getting on base, we need to divide the number of times the player got on base (7) by the total number of plate appearances (12), which is the sum of the number of times the player got on base and the number of times the player struck out:
Experimental probability of getting on base = $\frac{7}{7+5} = \frac{7}{12}$
Therefore, the answer is (B) 7/12.
You flip a coin 20 times and get tails 15 times. You flip the coin 80 more times. What do you expect to happen to the experimental probability of getting tails as you increase the number of trials?
A. The experimental probability will get closer to 50%.
B. The experimental probability will remain at 75%.
C. The experimental probability will always be greater than the theoretical probability.
D. The experimental probability will get closer to 100%.