Dylan and Isaac are working together on solving math problems. For every one problem that Dylan completes, Isaac completes four. If the number of problems solved by Isaac is twenty-six more than two times the number of problems solved by Dylan, how many problems has Isaac solved?
Let's say Dylan solved x problems.
If Isaac solved four problems for every one solved by Dylan, then the number of problems Isaac solved is 4x.
According to the problem, 4x = 2x + 26.
Subtracting 2x from both sides gives 2x = 26.
Dividing both sides by 2 gives x = 13.
Therefore, Dylan solved 13 problems, and Isaac solved 4 * 13 = 52 problems.
Let's find the number of problems Dylan has solved first.
Let's assume the number of problems Dylan has solved is "x".
Since for every one problem Dylan completes, Isaac completes four, the number of problems Isaac has solved is 4 * x.
According to the given information, the number of problems solved by Isaac is twenty-six more than two times the number of problems solved by Dylan. This can be written as:
4 * x = 2 * x + 26
Simplifying the equation, we get:
4 * x - 2 * x = 26
2 * x = 26
Dividing both sides by 2, we get:
x = 13
So, Dylan has solved 13 problems.
Now, let's find the number of problems Isaac has solved:
Isaac has solved 4 * x = 4 * 13 = 52 problems.
Therefore, Isaac has solved 52 problems.