At a summer camp, 20% of the students come from out of state. Megan wants to simulate cabins of 8 campers. She generates random digits from 0 to 9 and lets the digits 0 and 1 represent a camper from out of state. The table below shows her results.

69531217

89542756

89001254

01346895

12468503

20312346

79564328

59868542

75891003

56103249

58630126

57498510

76134860

52974168

03164985

03289642

68533236

94210145

70215789

32605254



What is the experimental probability that in a cabin of 8 campers, at least 2 are from out of state?

A. start fraction 7 over 20 end fraction
B. Start Fraction 13 over 20 End Fraction
C. start fraction 7 over 10 end fraction
D. four-fifths..

To determine the experimental probability that at least 2 out of 8 campers are from out of state, we need to analyze each number string and count how many 0's and 1's are in it. If there are 2 or more, we count it as a success. If there are fewer than 2, we count it as a failure.

Out of the 20 number strings given, the following have at least 2 0's or 1's:

- 69531217
- 89542756
- 89001254
- 01346895
- 12468503
- 20312346
- 79564328
- 59868542
- 75891003
- 56103249
- 58630126
- 57498510
- 76134860
- 52974168
- 03164985
- 03289642
- 94210145
- 70215789

That's a total of 18 successful number strings out of 20. Therefore, the experimental probability that in a cabin of 8 campers, at least 2 are from out of state is:

18/20 = 9/10 = Start Fraction 9 over 10 End Fraction

So the answer is (C) start fraction 7 over 10 end fraction.

To find the experimental probability that in a cabin of 8 campers, at least 2 are from out of state, we need to count the number of outcomes where at least 2 campers are from out of state and divide it by the total number of outcomes.

Looking at the given table, we can count the number of outcomes where at least 2 campers are from out of state:

6953 1 2 1 7
8 9 54 2 7 5 6
8 9 0 0 1 2 5 4
0 1 3 4 6 8 9 5
1 2 4 6 8 5 0 3
2 0 3 1 2 3 4 6
7 9 5 6 4 3 2 8
5 9 8 6 8 5 4 2
7 5 8 9 1 0 0 3

Upon counting, we can see that there are 7 outcomes where at least 2 campers are from out of state.

Since the table has 20 outcomes, we can now calculate the experimental probability:

Experimental Probability = Number of favorable outcomes / Total number of outcomes
Experimental Probability = 7 / 20

Therefore, the experimental probability that in a cabin of 8 campers, at least 2 are from out of state is 7/20, which is represented as Answer A: start fraction 7 over 20 end fraction.