Franco, who has a black belt in karate and kung fu, is practicing for an upcoming belt promotion test. During practice, he wants to run through the 3 weapon forms he knows. In how many different orders could Franco practice these forms?
orders
The number of different orders in which Franco can practice the weapon forms can be found using the permutation formula:
n!/(n-r)!
Where n is the total number of items and r is the number of items being chosen at a time. In this case, n = 3 (the number of weapon forms) and r = 3 (he wants to practice all three forms).
So the number of different orders Franco can practice the weapon forms is:
3!/(3-3)! = 3!/0! = 6
Therefore, Franco can practice the weapon forms in 6 different orders.
To calculate the number of different orders in which Franco can practice the forms, we can use the concept of permutations.
Since Franco wants to practice 3 weapon forms, we need to find the number of permutations of those 3 forms.
The formula to calculate permutations is given by:
P(n, r) = n! / (n - r)!
Where n is the total number of items and r is the number of items taken at a time.
In this case, n = 3 (the number of weapon forms Franco knows) and r = 3 (he wants to practice all of them).
Using the formula, we can calculate the number of permutations:
P(3, 3) = 3! / (3 - 3)!
= 3! / 0!
= 3! / 1
= 3 * 2 * 1 / 1
= 6
Therefore, Franco can practice his 3 weapon forms in 6 different orders.