A basket of fruit contains 5 banners, 8 mangos, and 7 apples. Calculate the probability of se an apple and a banana
The probability of selecting an apple is 7/(5+8+7) = 7/20.
The probability of selecting a banana is 5/(5+8+7) = 5/20.
Therefore, the probability of selecting an apple and a banana is (7/20) * (5/20) = 0.0875 or 8.75%.
To calculate the probability of selecting an apple and a banana from the basket of fruit, we need to find the probability of selecting an apple and multiply it by the probability of selecting a banana.
The probability of selecting an apple:
Given that there are a total of 5 bananas, 8 mangos, and 7 apples in the basket, the probability of selecting an apple is the number of apples divided by the total number of fruits:
P(apple) = number of apples / total number of fruits
P(apple) = 7 / (5 + 8 + 7)
P(apple) = 7 / 20
The probability of selecting a banana:
Similarly, the probability of selecting a banana is the number of bananas divided by the total number of fruits:
P(banana) = number of bananas / total number of fruits
P(banana) = 5 / (5 + 8 + 7)
P(banana) = 5 / 20
Now, we can calculate the probability of selecting both an apple and a banana by multiplying the two probabilities:
P(apple and banana) = P(apple) * P(banana)
P(apple and banana) = (7 / 20) * (5 / 20)
P(apple and banana) = 35 / 400
Thus, the probability of selecting an apple and a banana from the basket of fruit is 35/400.