Write an ionic equation for the reaction in the preparation of lead(2)iodide salt,including state symbols
Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq)
To write the ionic equation for the reaction in the preparation of lead(II) iodide salt, we first need to know the reactants involved in the process. The reactants are lead(II) nitrate and potassium iodide.
The chemical equation for the reaction is:
Lead(II) nitrate + potassium iodide → lead(II) iodide + potassium nitrate
To write the ionic equation, we need to separate the reactants and products into their respective ions and include state symbols.
The ionic equation for the reaction is:
Pb^2+(aq) + 2NO3^-(aq) + 2K+(aq) + 2I^-(aq) → PbI2(s) + 2K+(aq) + 2NO3^-(aq)
In this equation, "(aq)" represents aqueous, indicating that the species is dissolved in water, and "(s)" denotes solid, representing the formation of the lead(II) iodide salt.