A vehicle starts from rest and in 30s reaches a speed of 20s. Thereafter the speed remains steadily until it stops 5s later.
1. Use the data provided to draw a velocity time graph for the motion
2. Calculate the acceleration during the first 30s
3. What is the total distance covered by the vehicle
1.
2. Acceleration during the first 30s can be calculated using the formula:
acceleration = (final velocity - initial velocity)/time taken
Here, initial velocity = 0, final velocity = 20 m/s, time taken = 30 s
acceleration = (20-0)/30 = 0.67 m/s^2
3. Total distance covered can be calculated by dividing the motion into two parts:
a) During the first 30s, the acceleration was 0.67 m/s^2 and the initial velocity was 0 m/s.
Using the formula: distance = (initial velocity x time taken) + (0.5 x acceleration x time taken^2)
Distance covered = (0 x 30) + (0.5 x 0.67 x 30^2) = 603 m
b) During the next 5s, the speed remained constant at 20 m/s.
Distance covered = (velocity x time taken) = (20 x 5) = 100 m
Total distance covered = 603 + 100 = 703 m.
NO ===== Distance covered = (0 x 30) + (0.5 x 0.67 x 30^2) = 603 m xxxxxxxxxxx
I think Distance covered = (0 x 30) + (0.5 x 0.67 x 30^2) = 301.5 m
You are correct. Thank you for pointing that out. The correct calculation is:
Distance covered = (0 x 30) + (0.5 x 0.67 x 30^2) = 301.5 m.