How many grams of ammonia can be produced from 1.33 grams of nitrogen trichloride?
Nitrogen tricholoride gas reacts with water to produce ammonia and hypochlorous acid according to the following equation:
NCl3 + 3H2O → NH3 + 3HClO
To determine the amount of ammonia produced, we need to use stoichiometry and the molar masses of the compounds involved.
1. Write out the balanced chemical equation:
NCl3 + 3H2O --> NH3 + 3HClO
2. Calculate the molar mass of NCl3:
N = 14.01 g/mol
Cl = 35.45 g/mol (we have 3 Cl atoms)
Molar mass of NCl3 = 14.01 + (35.45 x 3) = 120.92 g/mol
3. Convert the given mass of NCl3 to moles:
1.33 g NCl3 x (1 mol / 120.92 g) = 0.011 mol NCl3
4. Use the mole ratio from the balanced equation to find the moles of NH3 produced:
1 mol NCl3 produces 1 mol NH3
0.011 mol NCl3 x (1 mol NH3 / 1 mol NCl3) = 0.011 mol NH3
5. Convert the moles of NH3 to grams:
Molar mass of NH3 = 17.03 g/mol
0.011 mol NH3 x (17.03 g / 1 mol) = 0.187 g NH3
Therefore, 0.187 grams of ammonia can be produced from 1.33 grams of nitrogen trichloride.
To determine the amount of ammonia that can be produced from a given amount of nitrogen trichloride, we need to use stoichiometry.
First, we need to calculate the molar mass of NCl3 (nitrogen trichloride) and NH3 (ammonia).
NCl3:
1 nitrogen atom weighs 14.01 g/mol
3 chlorine atoms weigh 3 * 35.45 g/mol = 106.35 g/mol
Total molar mass of NCl3 = 14.01 + 106.35 = 120.36 g/mol
NH3:
1 nitrogen atom weighs 14.01 g/mol
3 hydrogen atoms weigh 3 * 1.01 g/mol = 3.03 g/mol
Total molar mass of NH3 = 14.01 + 3.03 = 17.04 g/mol
Next, we need to determine the molar ratio between NCl3 and NH3 using the balanced chemical equation:
NCl3 + 3H2O → NH3 + 3HClO
From the equation, we can see that 1 mole of NCl3 reacts to produce 1 mole of NH3.
Now, let's calculate the number of moles of NCl3 in 1.33 grams:
moles of NCl3 = mass / molar mass
moles of NCl3 = 1.33 g / 120.36 g/mol
moles of NCl3 ≈ 0.0110 mol
Since the molar ratio is 1:1, we can say that 0.0110 moles of NCl3 will produce an equal amount of NH3.
Finally, let's calculate the mass of NH3 produced:
mass of NH3 = moles of NH3 * molar mass
mass of NH3 = 0.0110 mol * 17.04 g/mol
mass of NH3 ≈ 0.187 g
Therefore, approximately 0.187 grams of ammonia can be produced from 1.33 grams of nitrogen trichloride.