Find the value of 64÷4×2+(11-5)×4
Using the order of operations (PEMDAS), we first evaluate the parentheses:
11-5 = 6
Next, we perform multiplication and division from left to right:
64 ÷ 4 = 16
16 × 2 = 32
Now we substitute our values:
32 + 6 × 4
Performing multiplication:
32 + 24
Finally, we add:
56
Therefore, 64÷4×2+(11-5)×4 = 56.
To find the value of the expression 64÷4×2+(11-5)×4, we need to follow the order of operations (BEDMAS/BODMAS).
1. First, solve the division operation: 64 ÷ 4 = 16.
2. Next, perform the multiplication operation: 16 × 2 = 32.
3. Then, solve the subtraction operation within the parentheses: 11 - 5 = 6.
4. After that, multiply the result of the subtraction by 4: 6 × 4 = 24.
5. Finally, perform the addition operation: 32 + 24 = 56.
Therefore, the value of 64÷4×2+(11-5)×4 is 56.