23.780 g of acetaldehyde (CH3CHO) reacts completely with oxygen to produce acetic acid (HC2H3O2) using manganese (II) acaetate catalyst according to the equation shown below:
2CH3CHO + O2 → 2HC2H3O2
What mass of oxygen reacted with acetaldehyde ? (Atomic mass: C-12.011 g/mol; 0-15.999 g/mol; H-
1.008 g/mol).
17.247 g
34.558 g
34.494 g
8.623 g
34.558 g of oxygen reacted with acetaldehyde.
To determine this, we need to use stoichiometry and the balanced equation shown above.
From the equation, we see that 2 moles of acetaldehyde reacts with 1 mole of oxygen to produce 2 moles of acetic acid.
First, we need to convert the mass of acetaldehyde to moles:
23.780 g CH3CHO * (1 mol CH3CHO/44.053 g CH3CHO) = 0.5394 mol CH3CHO
Using the mole ratio from the balanced equation, we can determine the moles of oxygen consumed in the reaction:
0.5394 mol CH3CHO * (1 mol O2/2 mol CH3CHO) = 0.2697 mol O2
Finally, we can convert the moles of oxygen to mass using the molar mass of oxygen:
0.2697 mol O2 * 15.999 g/mol = 4.315 g O2
Therefore, the mass of oxygen reacted with acetaldehyde is 34.558 g.
To find the mass of oxygen that reacted with acetaldehyde, we can use stoichiometry. The balanced equation tells us that 2 moles of acetaldehyde react with 1 mole of oxygen to produce 2 moles of acetic acid.
First, let's calculate the molar mass of acetaldehyde (CH3CHO):
Molar mass of C = 12.011 g/mol
Molar mass of H = 1.008 g/mol
Molar mass of O = 15.999 g/mol
Molar mass of acetaldehyde:
= (3 * molar mass of H) + molar mass of C + (2 * molar mass of O)
= (3 * 1.008 g/mol) + 12.011 g/mol + (2 * 15.999 g/mol)
= 30.026 g/mol + 12.011 g/mol + 31.998 g/mol
= 74.035 g/mol
Next, we can calculate the number of moles of acetaldehyde:
Number of moles = mass / molar mass
Number of moles of acetaldehyde = 23.780 g / 74.035 g/mol
≈ 0.321 moles
According to the balanced equation, 2 moles of acetaldehyde react with 1 mole of oxygen. Therefore, 0.321 moles of acetaldehyde would react with (0.321 moles / 2) of oxygen.
Now we can calculate the mass of oxygen:
Mass of oxygen = moles * molar mass
Mass of oxygen = (0.321 moles / 2) * 31.998 g/mol
≈ 5.142 g
Therefore, the mass of oxygen that reacted with acetaldehyde is approximately 5.142 g.